Rewrote double function.

Also changed unit tests. The syntax qq = dates('Q'); qq(1950,1) does not
work anymore, most likely because of inplace modifications...
parent 36c1a646
function [B, C] = double(A) % --*-- Unitary tests --*--
function [m, f] = double(o) % --*-- Unitary tests --*--
% Returns a vector of doubles with the fractional part corresponding
% to the subperiod. Used for plots and to store dates in a matrix.
%
% INPUTS
% o A dates object.
% - o [dates]
%
% OUTPUTS
% o B A.ndat*1 vector of doubles.
% o C integer scalar, the frequency (1, 4, 12 or 52).
% - m [double] o.ndat*1 vector of doubles.
% - f [integer] scalar, the frequency (1, 4, 12 or 52).
%
% REMARKS
% Obviously the frequency is lost during the conversion.
% Copyright (C) 2013 Dynare Team
%
% This file is part of Dynare.
% Copyright (C) 2013-2014 Dynare Team
%
% Dynare is free software: you can redistribute it and/or modify
% This code is free software: you can redistribute it and/or modify
% it under the terms of the GNU General Public License as published by
% the Free Software Foundation, either version 3 of the License, or
% (at your option) any later version.
%
% Dynare is distributed in the hope that it will be useful,
% Dynare dates submodule is distributed in the hope that it will be useful,
% but WITHOUT ANY WARRANTY; without even the implied warranty of
% MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
% GNU General Public License for more details.
......@@ -30,15 +28,14 @@ function [B, C] = double(A) % --*-- Unitary tests --*--
% You should have received a copy of the GNU General Public License
% along with Dynare. If not, see <http://www.gnu.org/licenses/>.
B = A.time(:,1)+(A.time(:,2)-1)/A.freq;
m = o.time(:,1)+(o.time(:,2)-1)/o.freq;
if nargout>1
C = A.freq;
f = o.freq;
end
%@test:1
%$ % Define a dates object
%$ qq = dates('Q');
%$ B = qq(1950,1):qq(1951,1);
%$ B = dates('1950Q1'):dates('1951Q1');
%$
%$ % Call the tested routine.
%$ try
......@@ -58,14 +55,11 @@ end
%@eof:1
%@test:2
%$ % Define a dates object
%$ qq = dates('Q');
%$
%$ % Call the tested routine.
%$ try
%$ C = NaN(2,1);
%$ C(1) = double(qq(1950,1));
%$ C(2) = double(qq(1950,2));
%$ C(1) = double(dates('1950Q1'));
%$ C(2) = double(dates('1950Q2'));
%$ t(1) = 1;
%$ catch
%$ t(1) = 0;
......
Markdown is supported
0% or
You are about to add 0 people to the discussion. Proceed with caution.
Finish editing this message first!
Please register or to comment